0=-8x^2+50x

Solution for 0=-8x^2+50x equation:

0=-8x^2+50x

We move all terms to the left:

0-(-8x^2+50x)=0

We add all the numbers together, and all the variables

-(-8x^2+50x)=0

We get rid of parentheses

8x^2-50x=0

a = 8; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·8·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*8}=\frac{100}{16}
=6+1/4
$